Hi,
I have a very basic question. I wanted to compare 2D vs 3D Mohr Coulomb yield surface. I believe the 2D yield surface is part of 3D yield surface. I wanted to see the 2D part in 3D. But i am finding difficult to visualize in 3D which line could it be in 3D as i have in 2D. In 2D, I suppose sigma 2 is 0..
Could someone help me related 2D to 3D yield surface?
Thank You in advance
Br
Naren Gurung
mohr coulomb 2D yield surface vs 3D mohr coulomb yield surface 28.2.2026
Problem with GeoStudio (Seepage) software 16.2.2026
Prague Geotechnical Days 2026 3.2.2026
Postdoctoral position at COFS, UWA 28.7.2025
Hypoplasticity clay in ABAQUS 23.7.2025
Drucker-Prager Cap 29.5.2025
Abaqus RITSS with hypoplastic 9.4.2025
Fellin UMAT subroutine 2.4.2025
Hypoplasticity clay for triaxial compression in abaqus 26.3.2025
Abaqus RITSS methon for LDFE analysis with hypoplastic 17.3.2025
Request for VUMAT Implementation of Mohr-Coulomb, Drucker-Prager, or Drucker-Prager Cap 28.2.2025
Suggestions for an Advanced Constitutive Model in FEM-Based Dynamic Slope Stability Analysis 12.2.2025
©2026 SoilModels
dear Naren,
I m not sure what you want to see. But lets take phi=30 en c=0. In 2D you have yielding if S1/S3=3 or S3/S1=3 and S2 can be anything (accept S2 should be between S1 en S3: but that’s for later).
Same you can do for S1+S2 ans S2+S3: what remains (result of 6 lines in 2D= 6 planes in 3D) is the mohr coulomb cone. If you make a cut with isotropic plan (S1+S2+S3=constant) you wil get the irregular hexagon.